5.6 Answers to Questions

5.6 Answers to Questions

07 October 2011

11:53

Collins, p.107

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Notes:

ρfresh water = 1,000kg/m3

g = 10N/kg

1,000mbar = 1 bar = 100,000Pa

5. ∆p = h × ρ × g

250,000 - 100,000 = h x 1,000 x 10

h = 15m

· If he was diving in sea water then the depth would be slightly less. Why? From the equation...
· ∆p = same, g = same, ρ = less, therefore h must be more

· ρ = 0.42g/cm3 = 420kg/m3

∆p = h × ρ × g

∆p = 50 x 420 x 1.4

∆p =29,400Pa or 29kPa

1,000mbar = 1 bar = 100,000Pa

1,600mbar = 1.6 bar = 160,000Pa

So total pressure = 29,000+160,000 = 189,000Pa